(2x-3)(3x-5)=6x^2-x

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Solution for (2x-3)(3x-5)=6x^2-x equation: 



(2x-3)(3x-5)=6x^2-x

We move all terms to the left:

(2x-3)(3x-5)-(6x^2-x)=0

We get rid of parentheses

-6x^2+(2x-3)(3x-5)+x=0

We multiply parentheses ..

-6x^2+(+6x^2-10x-9x+15)+x=0

We get rid of parentheses

-6x^2+6x^2-10x-9x+x+15=0

We add all the numbers together, and all the variables

-18x+15=0

We move all terms containing x to the left, all other terms to the right

-18x=-15

x=-15/-18

x=5/6

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